Learn to debug program

Posted by Camille at November 12, 2016 - 7:36 AM

Hello, I compiled B and C output is 1234567890123456.000000, should how to debug.?

Posted by Quennel at November 20, 2016 - 7:47 AM

Posted by Quennel at December 02, 2016 - 7:59 AM

The result, because you give B and C data over the double and long double said. As for why the decimal part is 0, this would not have struggled, as long as you know the program has a problem on the line.

Posted by Roy at December 09, 2016 - 8:41 AM

Length: 16 bit decimal

No number of words, a total of 17

In your B, C the length is more than the upper limit, so the content does not belong to B and C

May happen to be 0? Or is this position by the 0 initialization?

No number of words, a total of 17

In your B, C the length is more than the upper limit, so the content does not belong to B and C

May happen to be 0? Or is this position by the 0 initialization?

Posted by Jo at December 12, 2016 - 9:06 AM

Beyond the effective range. . . . . . .

Posted by Lyle at December 27, 2016 - 9:25 AM

The integer part of the effective precision floating-point type occupied the entire

Because the integer part can be represented accurately, so the fractional part is all 0

Because the integer part can be represented accurately, so the fractional part is all 0

Posted by Ricky at January 01, 2017 - 10:16 AM

Posted by Samson at January 03, 2017 - 10:39 AM

#include <stdio.h> int main() { float a; double b; long double c; a=0.123456f; b=1.23456789012345e1; c=1.23456789012345e1; printf("a=%.6g\n",a); printf("b=%.15lg\n",b); printf("c=%.15lg\n",c); return 0; }

Reference resources:

include\float.h

... #define DBL_DIG 15 /* # of decimal digits of precision */ #define DBL_EPSILON 2.2204460492503131e-016 /* smallest such that 1.0+DBL_EPSILON != 1.0 */ #define DBL_MANT_DIG 53 /* # of bits in mantissa */ #define DBL_MAX 1.7976931348623158e+308 /* max value */ #define DBL_MAX_10_EXP 308 /* max decimal exponent */ #define DBL_MAX_EXP 1024 /* max binary exponent */ #define DBL_MIN 2.2250738585072014e-308 /* min positive value */ #define DBL_MIN_10_EXP (-307) /* min decimal exponent */ #define DBL_MIN_EXP (-1021) /* min binary exponent */ #define _DBL_RADIX 2 /* exponent radix */ #define _DBL_ROUNDS 1 /* addition rounding: near */ #define FLT_DIG 6 /* # of decimal digits of precision */ #define FLT_EPSILON 1.192092896e-07F /* smallest such that 1.0+FLT_EPSILON != 1.0 */ #define FLT_GUARD 0 #define FLT_MANT_DIG 24 /* # of bits in mantissa */ #define FLT_MAX 3.402823466e+38F /* max value */ #define FLT_MAX_10_EXP 38 /* max decimal exponent */ #define FLT_MAX_EXP 128 /* max binary exponent */ #define FLT_MIN 1.175494351e-38F /* min positive value */ #define FLT_MIN_10_EXP (-37) /* min decimal exponent */ #define FLT_MIN_EXP (-125) /* min binary exponent */ #define FLT_NORMALIZE 0 #define FLT_RADIX 2 /* exponent radix */ #define FLT_ROUNDS 1 /* addition rounding: near */ #define LDBL_DIG DBL_DIG /* # of decimal digits of precision */ #define LDBL_EPSILON DBL_EPSILON /* smallest such that 1.0+LDBL_EPSILON != 1.0 */ #define LDBL_MANT_DIG DBL_MANT_DIG /* # of bits in mantissa */ #define LDBL_MAX DBL_MAX /* max value */ #define LDBL_MAX_10_EXP DBL_MAX_10_EXP /* max decimal exponent */ #define LDBL_MAX_EXP DBL_MAX_EXP /* max binary exponent */ #define LDBL_MIN DBL_MIN /* min positive value */ #define LDBL_MIN_10_EXP DBL_MIN_10_EXP /* min decimal exponent */ #define LDBL_MIN_EXP DBL_MIN_EXP /* min binary exponent */ #define _LDBL_RADIX DBL_RADIX /* exponent radix */ #define _LDBL_ROUNDS DBL_ROUNDS /* addition rounding: near */ ...

Posted by Angelina at January 10, 2017 - 11:19 AM

Feeling or length of the problem

Posted by Hamiltion at January 11, 2017 - 12:01 PM

Why the fractional part of B and C is 000000.?

Started by Quennel at February 07, 2016 - 12:36 PM